i have a take-home test that i need to have done for tomorrow and i need help on this problem.

6x+y-4z=-8
y/4-z/6=0
2x-z=-2

anyone have any idea?

What are the directions?

you have to find the values for x, y, and z.

JENNI JUST POSTED A THREAD LIKE THIS.

I would ask Jenni. Her friend answered for her.

oh oh oh oh oh oh
hold on

oh crap, you have fractions with the variables?
i dont know how to do that
we're doing three variable things like that,
solve by substitution or linear combination, but fractions i havent done

that's what's throwing me off. i might just skip it even though this take-home test is a big grade. :P

I CAN HELP

i'll do an example problem just like that, i'll just change the numbers so i'm not doing the problem for you

and then when you get your real answer, i can do the problem too so you can check your answer

please and thank you!!

okay i'm not doing all that work, i'll just tell you what to do

in the 3rd equation, solve for z
then in the 2nd equation, solve for y

then plug your answer for y into the first equation,
then go back and plug in your answer for z= in this equation for all the z's

solve for x

using your answer for x, plug it into the third equation and solve for z
then plug z into the second equation and get y

then check your answers

i went to do an example problem and the numbers got crazy
haha sorry

it's ok. what did u get for y=? cause the way i'm trying to do it, i get y=4(z/6)

would u cross multiply 4 and z/6?

i got y= 4z/6

when i cross multiplied, i got 24z...

i don't think that's right.

nvm, i think i got it. i'll tell u what i got for x in a minute.

i got x=20
am i right so far?